Understanding Harmonics in Amateur Radio Bands

Transmitters ideally generate a single radio-frequency carrier. In reality, non-linear devices (amplifiers, mixers, oscillators) generate harmonics — unwanted frequencies that occur at integer multiples of the fundamental operating frequency.

Managing harmonic emissions is essential in amateur radio to:

  • Meet FCC spectral-purity requirements
  • Prevent interference to other services
  • Ensure amplifier and antenna efficiency
  • Maintain good operating practice

This article explains how harmonics are calculated and provides a full multi-band table of harmonic frequencies across the HF, VHF, and UHF amateur spectrum.


Where the Harmonic Formulas Come From

Harmonics arise from non-linear system behavior, which can be modeled as a polynomial expansion:x(t)=a1cos(2πft)+a2cos2(2πft)+a3cos3(2πft)+x(t) = a_1 \cos(2\pi f t) + a_2 \cos^2(2\pi f t) + a_3 \cos^3(2\pi f t)+\dotsx(t)=a1​cos(2πft)+a2​cos2(2πft)+a3​cos3(2πft)+…

Expanding the powers using trigonometric identities produces components at:f,  2f,  3f,  4f,f,\; 2f,\; 3f,\; 4f,\ldotsf,2f,3f,4f,…

These are the 1st, 2nd, 3rd, and 4th-order harmonics.

Harmonic Frequency Formula (from Fourier theory of nonlinear systems):fn=nf1f_n = n \cdot f_1fn​=n⋅f1​

Where:

  • f1f_1f1​ = fundamental (operating) frequency
  • nnn = harmonic number (1, 2, 3, 4 …)
  • fnf_nfn​ = frequency of the nth harmonic

This formula is derived directly from the mathematics of Fourier series and trigonometric power expansions, as found in:

  • The ARRL Handbook for Radio Communications
  • A. Oppenheim & A. Willsky, Signals and Systems
  • David M. Pozar, Microwave Engineering

Step-by-Step Example Calculation

Suppose you are transmitting on 40 meters (7.100 MHz).

1st harmonic (fundamental):

f1=17.100=7.100 MHzf_1 = 1 \cdot 7.100 = 7.100\text{ MHz}f1​=1⋅7.100=7.100 MHz

2nd harmonic:

f2=27.100=14.200 MHzf_2 = 2 \cdot 7.100 = 14.200\text{ MHz}f2​=2⋅7.100=14.200 MHz

3rd harmonic:

f3=37.100=21.300 MHzf_3 = 3 \cdot 7.100 = 21.300\text{ MHz}f3​=3⋅7.100=21.300 MHz

4th harmonic:

f4=47.100=28.400 MHzf_4 = 4 \cdot 7.100 = 28.400\text{ MHz}f4​=4⋅7.100=28.400 MHz

Notice how the harmonics fall inside other amateur bands, which is why filtering is critical.


Harmonics of Every Amateur Radio Band (1st–4th Order)

Notes

  • Frequencies use the approximate band centers commonly referenced for calculation.
  • Units are MHz for HF/VHF/UHF except 70 cm where GHz is more conventional.

Master Harmonic Table

Amateur BandFundamental (1st)2nd Harmonic3rd Harmonic4th Harmonic
160 m (1.85 MHz)1.853.705.557.40
80 m (3.65 MHz)3.657.3010.9514.60
40 m (7.10 MHz)7.1014.2021.3028.40
30 m (10.15 MHz)10.1520.3030.4540.60
20 m (14.20 MHz)14.2028.4042.6056.80
17 m (18.10 MHz)18.1036.2054.3072.40
15 m (21.25 MHz)21.2542.5063.7585.00
12 m (24.95 MHz)24.9549.9074.8599.80
10 m (28.50 MHz)28.5057.0085.50114.00
6 m (50.25 MHz)50.25100.50150.75201.00
2 m (146.00 MHz)146.0292.0438.0584.0
70 cm (440 MHz)0.440 GHz0.880 GHz1.320 GHz1.760 GHz

Why Harmonics Matter When Operating HF/VHF/UHF

1. Harmonics fall into other amateur bands

Example:
40 m → 2nd harmonic lands directly in 20 m.
15 m → 2nd harmonic lands exactly on 10 m.

2. Harmonics can interfere with non-amateur services

UHF harmonics may encroach on:

  • Aviation bands
  • Satellite downlinks
  • LTE cellular blocks
  • Public safety channels

3. Antennas may unintentionally radiate harmonics

Some antennas have gain peaks at harmonic frequencies.

4. Power amplifiers strongly magnify harmonic distortion

Class AB and C PA stages will produce nonlinear outputs unless low-pass filters are used.


How to Reduce Harmonic Emissions

Use proper low-pass filters (LPF)
Especially after power amplifiers.

Ensure clean drive levels
Overdriving creates nonlinearity → more harmonics.

Use well-designed antennas
High SWR and poor matching increases spurious radiation.

Verify with a spectrum analyzer or SDR
A TinySA, RTL-SDR, or Siglent SA can easily visualize harmonic content.


Conclusion

Harmonics in amateur radio occur at exact multiples of the fundamental frequency. The calculation is simple:fn=nf1f_n = n f_1fn​=nf1​

—but the operational implications are serious. Understanding where your 2nd, 3rd, and 4th-order harmonics fall helps ensure compliance, reduce interference, and maintain clean, efficient transmissions.

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